In order to solve problems which require application of the
area and
perimeter for rectangles, it is necessary to
A typical problem involving the
area and
perimeter of a
rectangle gives us the area,
perimeter and/or
length and width of the rectangle. We may also be given a relationship between the
area and
perimeter or between the
length and width of the rectangle. We need to calculate some of these quantities given information about the others.
To get started, relate the
length and width. We know that the
length is twice the width so
l = 2w
We know the
area is 32, so we use the
area formula for a rectangle:
lw = 2w(w) = 2w2 = 32
Solving for w:
2w2 = 32
w2 = 16
w = 4
l = 2w
l = 8
and the dimensions are 8 x 4.
The
perimeter is the sum of the lengths of all four sides or
2w + 2l = 2(4) + 2(8) = 24