In order to solve problems which involve secants, tangents, and segments formed by them, it is necessary to
A typical problem involving the segments formed by secants and tangents in a
circle gives us information about the measures of the secants and tangent and/or the segments formed when they intersect each other and the circle. Two examples of this type of problem are presented below.
- In circle O below (not drawn to scale), two secants from point P intersect circle O such that arcs CP = 10, BP = 9, CA = 2x, and BD = 2x +3. What is the measure of segment AP?
The products of the external
segment and the entire
secant must be equal for both secants. We have:
CP(CP + CA) = BP(BP + BD)
10(2x + 10) = 9(2x + 12)
20x + 100 = 18x + 108
2x = 8
x = 4
Since AP equals 2x + 10
AP = 2(4) + 10
AP = 18
- In circle O below (not drawn to scale), a tangent and secant are drawn from point P. We are given the following measurements: PC = x - 8, PB = 4, and BD = 12. What is the length of segment PC?
PC2 = PB(PB + BD)
This gives us
(x - 8)2 = 4(4 + 12) = 64
Expanding, we have
x2 - 16x + 64 = 64
x2 - 16x = 0
Solving for x
x(x - 16) = 0
x = 0 and x = 16
When we check x = 16 we get
PC = x - 8
PC = 16 - 8
PC = 8
Note that we cannot use x = 0 since it would give us PC = -8 and the
length of a segment cannot be a negative number.